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STTH12R06FP

STMicroelectronics

TURBO 2 ULTRAFAST HIGH VOLTAGE RECTIFIER - STMicroelectronics


STTH12R06FP
STTH12R06FP

PDF File STTH12R06FP PDF File



Description
® STTH12R06D/FP TURBO 2 ULTRAFAST HIGH VOLTAGE RECTIFIER MAIN PRODUCT CHARACTERISTICS IF(AV) VRRM IRM (typ.
) Tj (max) VF (max) trr (max) 12 A 600 V 7A 175 °C 1.
8 V 45 ns FEATURES AND BENEFITS s Ultrafast switching s Low reverse recovery current s Reduces switching losses s Low thermal resistance DESCRIPTION The STTH12R06D/FP, which is using ST Turbo 2 600V technology, is specially suited as boost diode in continuous mode power factor corrections and hard switching conditions.
The device is also intended for use as a free wheeling diode in power supplies and other power switching applications.
A K TO-220FPAC STTH12R06FP K A K TO-220AC STTH12R06D ABSOLUTE RATINGS (limiting values) Symbol Parameter VRRM Repetitive peak reverse voltage IF(RMS) RMS forward current IF(AV) Average forward current IFSM Surge non repetitive forward current tp = 10 ms Tstg Storage temperature range Tj Maximum operating junction temperature Sinusoidal Value 600 30 12 100 - 65 + 175 + 175 Unit V A A A °C °C January 2002 - Ed: 1B 1/6 STTH12R06D/FP THERMAL RESISTANCES Symbol Rth (j-c) Junction to case Parameter TO-220AC TO-220FPAC Value 1.
7 4.
4 Unit °C/W STATIC ELECTRICAL CHARACTERISTICS Symbol Parameter Tests conditions Min.
IR Reverse leakage current VR = 600V Tj = 25°C Tj = 125°C VF Forward voltage drop IF = 12 A Tj = 25°C Tj = 125°C To evaluate the maximum conduction losses use the following equation : P = 1.
16 x IF(AV) + 0.
053 IF2(RMS) Typ.
50 1.
4 Max.
45 600 2.
9 1.
8 Unit µA V DYNAMIC ELECTRICAL CHARACTERISTICS Symbol Tests conditions trr IF = 0.
5 A Irr = 0.
25 A IR = 1A IF = 1 A dIF/dt = - 50 A/µs VR = 30V IRM VR = 400 V IF = 12A S factor dIF/dt = - 200A/µs Qrr tfr IF = 12 A dIF/dt = 96 A/µs VFR = 1.
1 x VFmax VFP Tj = 25°C Min.
Typ.
Max.
Unit 25 ns 45 Tj = 125°C Tj = 25°C 7.
0 8.
4 A 0.
2 180 nC 200 ns 5.
5 V 2/6 Fig.
1: Conduction losses versus average current.
P(W) 30 25 20 δ = 0.
05 δ = 0.
1 δ = 0.
2 δ = 0.
5 δ=1 15 10 T 5 IF(av)(A) ...



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