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FPF2193 Datasheet
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Application Information
Figure 28. Typical Application
Setting Current Limit
The FPF2193, FPF2194, and FPF2195 current limit is
set with an external resistor connected between ISET and
GND. This resistor is selected using the following
equation:
RSET
=
551.6
ILIM
RSET is in Ω and ISET is in Amps.
(1)
Table 1 can also be used to select RSET. A typical
application would be the 500 mA current required by a
single USB port. Using Table 1, an appropriate selection
for the RSET resistor would be 788 . This ensures that
the port load could draw 525 mA, but not more than
875 mA. Likewise for a dual-port system; an RSET of
368 always delivers at least 1125 mA and never more
than 1875 mA.
Table 1. Current Limit Various RSET Values
RSET(Ω)
Min. Current
Limit (mA)
368 1125
441 928
552 750
613 675
690 600
788 525
919 450
1103
375
1226
338
1379
300
1576
263
1839
225
2206
188
2758
150
3677
113
5516
15800(4)
75
35
Typ. Current
Limit (mA)
1500
1250
1000
900
800
700
600
500
450
400
350
300
250
200
150
100
45
Max. Current
Limit (mA)
1875
1562
1250
1125
1000
875
750
625
563
500
438
375
313
250
188
125
60
Input Capacitor
To limit the voltage drop on the input supply caused by
transient inrush currents when the switch is turned on
into a discharged load capacitor or a short-circuit, a
capacitor needs to be placed between VIN and GND. A
0.1 µF ceramic capacitor, CIN, placed close to the pins is
usually sufficient. Higher values of CIN can be used to
further reduce the voltage drop.
Output Capacitor
A 0.1 µF capacitor, COUT, should be placed between
VOUT and GND. This capacitor prevents parasitic board
inductances from forcing VOUT below GND when the
switch turns off. For the FPF2193 and FPF2194, the
total output capacitance needs to be kept below a
maximum value, COUT(max), to prevent the part from
registering an over-current condition and turning off the
switch. The maximum output capacitance can be
determined from the following formula:
COUT(max)
=
ILIM(max)× tBLANK(min)
VIN
(2)
Power Dissipation
During normal operation as a switch, the power
dissipated depends upon the level at which the current
limit is set. The maximum allowed setting for the current
limit is 1.5 A and results in a power dissipation of:
P = (ILIM)2 ×RON = (1.5)2 × 0.055 = 123.75mW (3)
If the part goes into current limit, the maximum power
dissipation occurs when the output is shorted to ground.
For the FPF2193, the power dissipation scales by the
auto-restart time, tRSTRT, and the over-current blanking
time, tBLANK, so that the maximum power dissipated is:
P(max) =
tBLANK
tBLANK + tRSTRT
× VIN(max)×ILIM(max)
=
30
30 + 450
× 5.5 ×1.5
=
515.6mW
(4)
Note:
4. FPF2195BUCX only.
© 2009 Fairchild Semiconductor Corporation
FPF2193/4/5 • Rev. 1.0.9
11
www.fairchildsemi.com

FPF2193 Datasheet PDF



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